YES

We show the termination of the TRS R:

  eq(|0|(),|0|()) -> true()
  eq(|0|(),s(x)) -> false()
  eq(s(x),|0|()) -> false()
  eq(s(x),s(y)) -> eq(x,y)
  or(true(),y) -> true()
  or(false(),y) -> y
  union(empty(),h) -> h
  union(edge(x,y,i),h) -> edge(x,y,union(i,h))
  reach(x,y,empty(),h) -> false()
  reach(x,y,edge(u,v,i),h) -> if_reach_1(eq(x,u),x,y,edge(u,v,i),h)
  if_reach_1(true(),x,y,edge(u,v,i),h) -> if_reach_2(eq(y,v),x,y,edge(u,v,i),h)
  if_reach_2(true(),x,y,edge(u,v,i),h) -> true()
  if_reach_2(false(),x,y,edge(u,v,i),h) -> or(reach(x,y,i,h),reach(v,y,union(i,h),empty()))
  if_reach_1(false(),x,y,edge(u,v,i),h) -> reach(x,y,i,edge(u,v,h))

-- SCC decomposition.

Consider the dependency pair problem (P, R), where P consists of

p1: eq#(s(x),s(y)) -> eq#(x,y)
p2: union#(edge(x,y,i),h) -> union#(i,h)
p3: reach#(x,y,edge(u,v,i),h) -> if_reach_1#(eq(x,u),x,y,edge(u,v,i),h)
p4: reach#(x,y,edge(u,v,i),h) -> eq#(x,u)
p5: if_reach_1#(true(),x,y,edge(u,v,i),h) -> if_reach_2#(eq(y,v),x,y,edge(u,v,i),h)
p6: if_reach_1#(true(),x,y,edge(u,v,i),h) -> eq#(y,v)
p7: if_reach_2#(false(),x,y,edge(u,v,i),h) -> or#(reach(x,y,i,h),reach(v,y,union(i,h),empty()))
p8: if_reach_2#(false(),x,y,edge(u,v,i),h) -> reach#(x,y,i,h)
p9: if_reach_2#(false(),x,y,edge(u,v,i),h) -> reach#(v,y,union(i,h),empty())
p10: if_reach_2#(false(),x,y,edge(u,v,i),h) -> union#(i,h)
p11: if_reach_1#(false(),x,y,edge(u,v,i),h) -> reach#(x,y,i,edge(u,v,h))

and R consists of:

r1: eq(|0|(),|0|()) -> true()
r2: eq(|0|(),s(x)) -> false()
r3: eq(s(x),|0|()) -> false()
r4: eq(s(x),s(y)) -> eq(x,y)
r5: or(true(),y) -> true()
r6: or(false(),y) -> y
r7: union(empty(),h) -> h
r8: union(edge(x,y,i),h) -> edge(x,y,union(i,h))
r9: reach(x,y,empty(),h) -> false()
r10: reach(x,y,edge(u,v,i),h) -> if_reach_1(eq(x,u),x,y,edge(u,v,i),h)
r11: if_reach_1(true(),x,y,edge(u,v,i),h) -> if_reach_2(eq(y,v),x,y,edge(u,v,i),h)
r12: if_reach_2(true(),x,y,edge(u,v,i),h) -> true()
r13: if_reach_2(false(),x,y,edge(u,v,i),h) -> or(reach(x,y,i,h),reach(v,y,union(i,h),empty()))
r14: if_reach_1(false(),x,y,edge(u,v,i),h) -> reach(x,y,i,edge(u,v,h))

The estimated dependency graph contains the following SCCs:

  {p3, p5, p8, p9, p11}
  {p1}
  {p2}


-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: if_reach_2#(false(),x,y,edge(u,v,i),h) -> reach#(v,y,union(i,h),empty())
p2: reach#(x,y,edge(u,v,i),h) -> if_reach_1#(eq(x,u),x,y,edge(u,v,i),h)
p3: if_reach_1#(false(),x,y,edge(u,v,i),h) -> reach#(x,y,i,edge(u,v,h))
p4: if_reach_1#(true(),x,y,edge(u,v,i),h) -> if_reach_2#(eq(y,v),x,y,edge(u,v,i),h)
p5: if_reach_2#(false(),x,y,edge(u,v,i),h) -> reach#(x,y,i,h)

and R consists of:

r1: eq(|0|(),|0|()) -> true()
r2: eq(|0|(),s(x)) -> false()
r3: eq(s(x),|0|()) -> false()
r4: eq(s(x),s(y)) -> eq(x,y)
r5: or(true(),y) -> true()
r6: or(false(),y) -> y
r7: union(empty(),h) -> h
r8: union(edge(x,y,i),h) -> edge(x,y,union(i,h))
r9: reach(x,y,empty(),h) -> false()
r10: reach(x,y,edge(u,v,i),h) -> if_reach_1(eq(x,u),x,y,edge(u,v,i),h)
r11: if_reach_1(true(),x,y,edge(u,v,i),h) -> if_reach_2(eq(y,v),x,y,edge(u,v,i),h)
r12: if_reach_2(true(),x,y,edge(u,v,i),h) -> true()
r13: if_reach_2(false(),x,y,edge(u,v,i),h) -> or(reach(x,y,i,h),reach(v,y,union(i,h),empty()))
r14: if_reach_1(false(),x,y,edge(u,v,i),h) -> reach(x,y,i,edge(u,v,h))

The set of usable rules consists of

  r1, r2, r3, r4, r7, r8

Take the reduction pair:

  lexicographic combination of reduction pairs:
  
    1. weighted path order
    
      base order:
    
        matrix interpretations:
        
          carrier: N^2
          order: lexicographic order
          interpretations:
            if_reach_2#_A(x1,x2,x3,x4,x5) = ((1,0),(1,1)) x4 + x5 + (8,1)
            false_A() = (2,2)
            edge_A(x1,x2,x3) = ((1,0),(0,0)) x1 + x3 + (8,2)
            reach#_A(x1,x2,x3,x4) = ((1,0),(1,1)) x3 + x4 + (9,11)
            union_A(x1,x2) = ((1,0),(1,0)) x1 + ((1,0),(1,1)) x2 + (3,12)
            empty_A() = (3,1)
            if_reach_1#_A(x1,x2,x3,x4,x5) = ((0,0),(1,0)) x1 + ((1,0),(1,1)) x4 + x5 + (9,1)
            eq_A(x1,x2) = (9,4)
            true_A() = (9,4)
            |0|_A() = (10,3)
            s_A(x1) = (10,5)
    
      precedence:
      
        edge = union = empty = |0| > eq = true = s > false > if_reach_2# = reach# = if_reach_1#
      
      partial status:
    
        pi(if_reach_2#) = [5]
        pi(false) = []
        pi(edge) = []
        pi(reach#) = []
        pi(union) = []
        pi(empty) = []
        pi(if_reach_1#) = [5]
        pi(eq) = []
        pi(true) = []
        pi(|0|) = []
        pi(s) = []
    
    2. weighted path order
    
      base order:
    
        matrix interpretations:
        
          carrier: N^2
          order: lexicographic order
          interpretations:
            if_reach_2#_A(x1,x2,x3,x4,x5) = (3,4)
            false_A() = (5,6)
            edge_A(x1,x2,x3) = (0,2)
            reach#_A(x1,x2,x3,x4) = (3,4)
            union_A(x1,x2) = (0,7)
            empty_A() = (4,5)
            if_reach_1#_A(x1,x2,x3,x4,x5) = (3,4)
            eq_A(x1,x2) = (2,1)
            true_A() = (1,3)
            |0|_A() = (6,7)
            s_A(x1) = (6,7)
    
      precedence:
      
        |0| > empty > union > edge > if_reach_2# = false = reach# = if_reach_1# > eq > true > s
      
      partial status:
    
        pi(if_reach_2#) = []
        pi(false) = []
        pi(edge) = []
        pi(reach#) = []
        pi(union) = []
        pi(empty) = []
        pi(if_reach_1#) = []
        pi(eq) = []
        pi(true) = []
        pi(|0|) = []
        pi(s) = []
    

The next rules are strictly ordered:

  p1, p3

We remove them from the problem.

-- SCC decomposition.

Consider the dependency pair problem (P, R), where P consists of

p1: reach#(x,y,edge(u,v,i),h) -> if_reach_1#(eq(x,u),x,y,edge(u,v,i),h)
p2: if_reach_1#(true(),x,y,edge(u,v,i),h) -> if_reach_2#(eq(y,v),x,y,edge(u,v,i),h)
p3: if_reach_2#(false(),x,y,edge(u,v,i),h) -> reach#(x,y,i,h)

and R consists of:

r1: eq(|0|(),|0|()) -> true()
r2: eq(|0|(),s(x)) -> false()
r3: eq(s(x),|0|()) -> false()
r4: eq(s(x),s(y)) -> eq(x,y)
r5: or(true(),y) -> true()
r6: or(false(),y) -> y
r7: union(empty(),h) -> h
r8: union(edge(x,y,i),h) -> edge(x,y,union(i,h))
r9: reach(x,y,empty(),h) -> false()
r10: reach(x,y,edge(u,v,i),h) -> if_reach_1(eq(x,u),x,y,edge(u,v,i),h)
r11: if_reach_1(true(),x,y,edge(u,v,i),h) -> if_reach_2(eq(y,v),x,y,edge(u,v,i),h)
r12: if_reach_2(true(),x,y,edge(u,v,i),h) -> true()
r13: if_reach_2(false(),x,y,edge(u,v,i),h) -> or(reach(x,y,i,h),reach(v,y,union(i,h),empty()))
r14: if_reach_1(false(),x,y,edge(u,v,i),h) -> reach(x,y,i,edge(u,v,h))

The estimated dependency graph contains the following SCCs:

  {p1, p2, p3}


-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: reach#(x,y,edge(u,v,i),h) -> if_reach_1#(eq(x,u),x,y,edge(u,v,i),h)
p2: if_reach_1#(true(),x,y,edge(u,v,i),h) -> if_reach_2#(eq(y,v),x,y,edge(u,v,i),h)
p3: if_reach_2#(false(),x,y,edge(u,v,i),h) -> reach#(x,y,i,h)

and R consists of:

r1: eq(|0|(),|0|()) -> true()
r2: eq(|0|(),s(x)) -> false()
r3: eq(s(x),|0|()) -> false()
r4: eq(s(x),s(y)) -> eq(x,y)
r5: or(true(),y) -> true()
r6: or(false(),y) -> y
r7: union(empty(),h) -> h
r8: union(edge(x,y,i),h) -> edge(x,y,union(i,h))
r9: reach(x,y,empty(),h) -> false()
r10: reach(x,y,edge(u,v,i),h) -> if_reach_1(eq(x,u),x,y,edge(u,v,i),h)
r11: if_reach_1(true(),x,y,edge(u,v,i),h) -> if_reach_2(eq(y,v),x,y,edge(u,v,i),h)
r12: if_reach_2(true(),x,y,edge(u,v,i),h) -> true()
r13: if_reach_2(false(),x,y,edge(u,v,i),h) -> or(reach(x,y,i,h),reach(v,y,union(i,h),empty()))
r14: if_reach_1(false(),x,y,edge(u,v,i),h) -> reach(x,y,i,edge(u,v,h))

The set of usable rules consists of

  r1, r2, r3, r4

Take the reduction pair:

  lexicographic combination of reduction pairs:
  
    1. weighted path order
    
      base order:
    
        max/plus interpretations on natural numbers:
        
          reach#_A(x1,x2,x3,x4) = x3 + 9
          edge_A(x1,x2,x3) = max{18, x1 - 4, x3 + 8}
          if_reach_1#_A(x1,x2,x3,x4,x5) = max{x1 + 19, x4 + 1}
          eq_A(x1,x2) = 4
          true_A = 0
          if_reach_2#_A(x1,x2,x3,x4,x5) = max{x1 + 6, x4 + 1}
          false_A = 0
          |0|_A = 1
          s_A(x1) = max{10, x1 + 9}
    
      precedence:
      
        if_reach_1# > reach# = if_reach_2# > edge = eq = true = false = |0| = s
      
      partial status:
    
        pi(reach#) = []
        pi(edge) = [3]
        pi(if_reach_1#) = [1, 4]
        pi(eq) = []
        pi(true) = []
        pi(if_reach_2#) = [1, 4]
        pi(false) = []
        pi(|0|) = []
        pi(s) = [1]
    
    2. weighted path order
    
      base order:
    
        max/plus interpretations on natural numbers:
        
          reach#_A(x1,x2,x3,x4) = 5
          edge_A(x1,x2,x3) = max{6, x3}
          if_reach_1#_A(x1,x2,x3,x4,x5) = x1
          eq_A(x1,x2) = 3
          true_A = 5
          if_reach_2#_A(x1,x2,x3,x4,x5) = x1 + 1
          false_A = 4
          |0|_A = 0
          s_A(x1) = x1 + 5
    
      precedence:
      
        true > reach# = edge = if_reach_1# = eq = if_reach_2# = false = |0| = s
      
      partial status:
    
        pi(reach#) = []
        pi(edge) = [3]
        pi(if_reach_1#) = [1]
        pi(eq) = []
        pi(true) = []
        pi(if_reach_2#) = [1]
        pi(false) = []
        pi(|0|) = []
        pi(s) = [1]
    

The next rules are strictly ordered:

  p1, p2, p3

We remove them from the problem.  Then no dependency pair remains.

-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: eq#(s(x),s(y)) -> eq#(x,y)

and R consists of:

r1: eq(|0|(),|0|()) -> true()
r2: eq(|0|(),s(x)) -> false()
r3: eq(s(x),|0|()) -> false()
r4: eq(s(x),s(y)) -> eq(x,y)
r5: or(true(),y) -> true()
r6: or(false(),y) -> y
r7: union(empty(),h) -> h
r8: union(edge(x,y,i),h) -> edge(x,y,union(i,h))
r9: reach(x,y,empty(),h) -> false()
r10: reach(x,y,edge(u,v,i),h) -> if_reach_1(eq(x,u),x,y,edge(u,v,i),h)
r11: if_reach_1(true(),x,y,edge(u,v,i),h) -> if_reach_2(eq(y,v),x,y,edge(u,v,i),h)
r12: if_reach_2(true(),x,y,edge(u,v,i),h) -> true()
r13: if_reach_2(false(),x,y,edge(u,v,i),h) -> or(reach(x,y,i,h),reach(v,y,union(i,h),empty()))
r14: if_reach_1(false(),x,y,edge(u,v,i),h) -> reach(x,y,i,edge(u,v,h))

The set of usable rules consists of

  (no rules)

Take the reduction pair:

  lexicographic combination of reduction pairs:
  
    1. weighted path order
    
      base order:
    
        max/plus interpretations on natural numbers:
        
          eq#_A(x1,x2) = max{2, x1 - 1, x2 + 1}
          s_A(x1) = max{1, x1}
    
      precedence:
      
        eq# = s
      
      partial status:
    
        pi(eq#) = [2]
        pi(s) = [1]
    
    2. weighted path order
    
      base order:
    
        max/plus interpretations on natural numbers:
        
          eq#_A(x1,x2) = 0
          s_A(x1) = max{2, x1}
    
      precedence:
      
        eq# = s
      
      partial status:
    
        pi(eq#) = []
        pi(s) = [1]
    

The next rules are strictly ordered:

  p1

We remove them from the problem.  Then no dependency pair remains.

-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: union#(edge(x,y,i),h) -> union#(i,h)

and R consists of:

r1: eq(|0|(),|0|()) -> true()
r2: eq(|0|(),s(x)) -> false()
r3: eq(s(x),|0|()) -> false()
r4: eq(s(x),s(y)) -> eq(x,y)
r5: or(true(),y) -> true()
r6: or(false(),y) -> y
r7: union(empty(),h) -> h
r8: union(edge(x,y,i),h) -> edge(x,y,union(i,h))
r9: reach(x,y,empty(),h) -> false()
r10: reach(x,y,edge(u,v,i),h) -> if_reach_1(eq(x,u),x,y,edge(u,v,i),h)
r11: if_reach_1(true(),x,y,edge(u,v,i),h) -> if_reach_2(eq(y,v),x,y,edge(u,v,i),h)
r12: if_reach_2(true(),x,y,edge(u,v,i),h) -> true()
r13: if_reach_2(false(),x,y,edge(u,v,i),h) -> or(reach(x,y,i,h),reach(v,y,union(i,h),empty()))
r14: if_reach_1(false(),x,y,edge(u,v,i),h) -> reach(x,y,i,edge(u,v,h))

The set of usable rules consists of

  (no rules)

Take the reduction pair:

  lexicographic combination of reduction pairs:
  
    1. weighted path order
    
      base order:
    
        max/plus interpretations on natural numbers:
        
          union#_A(x1,x2) = max{x1 + 1, x2}
          edge_A(x1,x2,x3) = x3
    
      precedence:
      
        union# = edge
      
      partial status:
    
        pi(union#) = [1, 2]
        pi(edge) = [3]
    
    2. weighted path order
    
      base order:
    
        max/plus interpretations on natural numbers:
        
          union#_A(x1,x2) = max{x1 - 1, x2 + 1}
          edge_A(x1,x2,x3) = x3
    
      precedence:
      
        union# = edge
      
      partial status:
    
        pi(union#) = []
        pi(edge) = [3]
    

The next rules are strictly ordered:

  p1

We remove them from the problem.  Then no dependency pair remains.